(x+2)(x-1)=x^2+1

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Solution for (x+2)(x-1)=x^2+1 equation: 



(x+2)(x-1)=x^2+1

We move all terms to the left:

(x+2)(x-1)-(x^2+1)=0

We get rid of parentheses

-x^2+(x+2)(x-1)-1=0

We multiply parentheses ..

-x^2+(+x^2-1x+2x-2)-1=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-1x+2x-2)-1=0

We get rid of parentheses

-1x^2+x^2-1x+2x-2-1=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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